Pengambilan peluang dengan sketsa grafik

Diketahui\(\mu=200cm,\)n=103, \(\sigma = 10.\)
Dapat diselesaikan menggunakan Tabel Z.

a. Kurang dari 180cm\[\begin{aligned}P(X<180)&=P(Z<\frac{\bar{X}-\mu}{\sigma })\\&= P(Z<\frac{180-200}{10})\\&= P(Z<-2)\end{aligned}\]b. Lebih dari 210 cm\[\begin{aligned}P(X>210)\\&=P(Z>\frac{210-200}{10})\end{aligned}\]c. Antara 190 sd 210 cm \[\begin{aligned}P(190<X<210)\\&= P(\frac{190-200}{10}<Z<\frac{210-200}{10})\end{aligned}\]d. Minimal 180 cm\[\begin{aligned}P(X\geq 180)\\&= P(Z\geq \frac{180-200}{10})\end{aligned}\]e. Paling banyak 210 cm\[\begin{aligned}P(X\leq 210)\\&=P(Z\leq \frac{210-200}{10})\end{aligned}\]