Peluang Distribusi Binomial

Question

X berdistribusi binomial dengan n = 2.000 dan π 0,5, tentukan P (X<=1.800)

rahmayetty · Answer

Diketahui $\pi=0\text{,}5$, $n=2000$, $x=1800$
$$\begin{aligned}P(X=x)&=\left( \begin{matrix}n \x\\end{matrix} \right)\pi^{x}(1-\pi)^{n-x}\end{aligned}$$
$$\begin{aligned}P(X<x)&=\sum_{x=0}^{n}P(X=x)\&=\sum_{x=0}^{n}P(X=0)+P(X=1)+...P(X=1800)\&=...\end{aligned}$$